20231227 Finished

src/solution/mod.rs

@@ -7,5 +7,6 @@ mod s0003_longest_substring_without_repeating_characters;
 mod s0162_find_peak_element;
 mod s2828_check_if_a_string_is_an_acronym_of_words;
 mod s0052_n_queens_ii;
+mod s0912_sort_an_array;
 mod s1276_number_of_burgers_with_no_waste_of_ingredients;
 mod s0006_zigzag_conversion;

src/solution/s0912_sort_an_array.rs

@@ -0,0 +1,95 @@
+/**
+ * [912] Sort an Array
+ *
+ * Given an array of integers nums, sort the array in ascending order and return it.
+ * You must solve the problem without using any built-in functions in O(nlog(n)) time complexity and with the smallest space complexity possible.
+ *  
+ * <strong class="example">Example 1:
+ * 
+ * Input: nums = [5,2,3,1]
+ * Output: [1,2,3,5]
+ * Explanation: After sorting the array, the positions of some numbers are not changed (for example, 2 and 3), while the positions of other numbers are changed (for example, 1 and 5).
+ * 
+ * <strong class="example">Example 2:
+ * 
+ * Input: nums = [5,1,1,2,0,0]
+ * Output: [0,0,1,1,2,5]
+ * Explanation: Note that the values of nums are not necessairly unique.
+ * 
+ *  
+ * Constraints:
+ * 
+ * 	1 <= nums.length <= 5 * 10^4
+ * 	-5 * 10^4 <= nums[i] <= 5 * 10^4
+ * 
+ */
+pub struct Solution {}
+
+// problem: https://leetcode.cn/problems/sort-an-array/
+// discuss: https://leetcode.cn/problems/sort-an-array/discuss/?currentPage=1&orderBy=most_votes&query=
+
+// submission codes start here
+
+impl Solution {
+    pub fn sort_array(nums: Vec<i32>) -> Vec<i32> {
+        let mut nums = nums;
+        let mut temp = Vec::with_capacity(nums.len());
+        temp.resize(nums.len(), 0);
+        let (left, right) = (0, nums.len() - 1);
+
+        Solution::merge_sort(&mut nums, &mut temp, left, right);
+        nums
+    }
+
+    fn merge_sort(nums: &mut Vec<i32>, temp: &mut Vec<i32>, left: usize, right: usize) {
+        if left >= right {
+            return;
+        }
+
+        let mid = (left + right) / 2;
+        Solution::merge_sort(nums, temp, left, mid);
+        Solution::merge_sort(nums, temp, mid + 1, right);
+
+        let (mut l, mut r, mut pos) = (left, mid + 1, left);
+
+        while l <= mid && r <= right {
+            if nums[l] <= nums[r] {
+                temp[pos] = nums[l];
+                l += 1;
+            } else {
+                temp[pos] = nums[r];
+                r += 1;
+            }
+            pos += 1;
+        }
+
+        while l <= mid {
+            temp[pos] = nums[l];
+            pos += 1;
+            l += 1;
+        }
+
+        while r <= right {
+            temp[pos] = nums[r];
+            pos += 1;
+            r += 1;
+        }
+
+        for i in left..=right {
+            nums[i] = temp[i];
+        }
+    }
+}
+
+// submission codes end
+
+#[cfg(test)]
+mod tests {
+    use super::*;
+
+    #[test]
+    fn test_912() {
+        assert_eq!(vec![1, 2, 3, 5], Solution::sort_array(vec![5, 2, 3, 1]));
+        assert_eq!(vec![0, 0, 1, 1, 2, 5], Solution::sort_array(vec![5, 1, 1, 2, 0, 0]));
+    }
+}