20231214 Finished

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jackfiled 2023-12-14 13:21:59 +08:00
parent 10780a5d99
commit 658691bdf8
2 changed files with 123 additions and 0 deletions

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@ -2,3 +2,4 @@ mod s0001_two_sum;
mod s0009_palindrome_number; mod s0009_palindrome_number;
mod s0020_valid_parentheses; mod s0020_valid_parentheses;
mod s2697_lexicographically_smallest_palindrome; mod s2697_lexicographically_smallest_palindrome;
mod s0002_add_two_numbers;

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@ -0,0 +1,122 @@
/**
* [2] Add Two Numbers
*
* You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
* You may assume the two numbers do not contain any leading zero, except the number 0 itself.
*
* <strong class="example">Example 1:
* <img alt="" src="https://assets.leetcode.com/uploads/2020/10/02/addtwonumber1.jpg" style="width: 483px; height: 342px;" />
* Input: l1 = [2,4,3], l2 = [5,6,4]
* Output: [7,0,8]
* Explanation: 342 + 465 = 807.
*
* <strong class="example">Example 2:
*
* Input: l1 = [0], l2 = [0]
* Output: [0]
*
* <strong class="example">Example 3:
*
* Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
* Output: [8,9,9,9,0,0,0,1]
*
*
* Constraints:
*
* The number of nodes in each linked list is in the range [1, 100].
* 0 <= Node.val <= 9
* It is guaranteed that the list represents a number that does not have leading zeros.
*
*/
pub struct Solution {}
use crate::util::linked_list::{ListNode, to_list};
// problem: https://leetcode.cn/problems/add-two-numbers/
// discuss: https://leetcode.cn/problems/add-two-numbers/discuss/?currentPage=1&orderBy=most_votes&query=
// submission codes start here
// Definition for singly-linked list.
// #[derive(PartialEq, Eq, Clone, Debug)]
// pub struct ListNode {
// pub val: i32,
// pub next: Option<Box<ListNode>>
// }
//
// impl ListNode {
// #[inline]
// fn new(val: i32) -> Self {
// ListNode {
// next: None,
// val
// }
// }
// }
impl Solution {
pub fn add_two_numbers(l1: Option<Box<ListNode>>, l2: Option<Box<ListNode>>)
-> Option<Box<ListNode>> {
let (mut left, mut right) = (l1, l2);
let mut dummy_head = Some(Box::new(ListNode::new(0)));
let mut now = &mut dummy_head;
let mut overflow = 0;
loop {
if left.is_none() && right.is_none() && overflow == 0 {
break
}
let left_value = match left {
None => {
0
}
Some(node) => {
left = node.next;
node.val
}
};
let right_value = match right {
None => {
0
}
Some(node) => {
right = node.next;
node.val
}
};
let value = overflow + left_value + right_value;
overflow = value / 10;
now.as_mut().unwrap().next = Some(Box::new(ListNode::new(value % 10)));
now = &mut now.as_mut().unwrap().next;
}
dummy_head.unwrap().next
}
}
// submission codes end
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn test_2() {
assert_eq!(
Solution::add_two_numbers(to_list(vec![2, 4, 3]), to_list(vec![5, 6, 4])),
to_list(vec![7, 0, 8])
);
assert_eq!(
Solution::add_two_numbers(to_list(vec![9, 9, 9, 9]), to_list(vec![9, 9, 9, 9, 9, 9])),
to_list(vec![8, 9, 9, 9, 0, 0, 1])
);
assert_eq!(
Solution::add_two_numbers(to_list(vec![0]), to_list(vec![0])),
to_list(vec![0])
);
}
}