20231212 Finished
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commit.sh
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commit.sh
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#!/bin/sh
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set -e
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time=$(date "+%Y%m%d")
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message="$time Finished"
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git add -A
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git commit -m "$message"
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git push
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src/problem/mod.rs
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src/problem/mod.rs
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src/solution/mod.rs
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src/solution/mod.rs
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mod s0001_two_sum;
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src/solution/s0001_two_sum.rs
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src/solution/s0001_two_sum.rs
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/**
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* [1] Two Sum
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*
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* Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
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* You may assume that each input would have exactly one solution, and you may not use the same element twice.
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* You can return the answer in any order.
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*
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* <strong class="example">Example 1:
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*
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* Input: nums = [2,7,11,15], target = 9
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* Output: [0,1]
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* Explanation: Because nums[0] + nums[1] == 9, we return [0, 1].
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*
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* <strong class="example">Example 2:
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*
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* Input: nums = [3,2,4], target = 6
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* Output: [1,2]
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*
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* <strong class="example">Example 3:
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*
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* Input: nums = [3,3], target = 6
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* Output: [0,1]
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*
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*
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* Constraints:
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*
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* 2 <= nums.length <= 10^4
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* -10^9 <= nums[i] <= 10^9
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* -10^9 <= target <= 10^9
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* Only one valid answer exists.
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*
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*
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* Follow-up: Can you come up with an algorithm that is less than O(n^2)<font face="monospace"> </font>time complexity?
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*/
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pub struct Solution {}
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// problem: https://leetcode.cn/problems/two-sum/
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// discuss: https://leetcode.cn/problems/two-sum/discuss/?currentPage=1&orderBy=most_votes&query=
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// submission codes start here
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use std::collections::HashMap;
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impl Solution {
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pub fn two_sum(nums: Vec<i32>, target: i32) -> Vec<i32> {
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let mut map = HashMap::with_capacity(nums.len());
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for (index, value) in nums.iter().enumerate() {
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match map.get(&(target - value)) {
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None => {
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map.insert(value, index);
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}
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Some(target_index) => {
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return vec![*target_index as i32, index as i32];
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}
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}
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}
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vec![]
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}
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}
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// submission codes end
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#[cfg(test)]
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mod tests {
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use super::*;
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#[test]
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fn test_1() {
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assert_eq!(vec![0, 1], Solution::two_sum(vec![2, 7, 11, 15], 9));
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assert_eq!(vec![1, 2], Solution::two_sum(vec![3, 2, 4], 6));
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}
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}
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