/**
 * [9] Palindrome Number
 *
 * Given an integer x, return true if x is a palindrome, and false otherwise.
 *  
 * Example 1:
 * 
 * Input: x = 121
 * Output: true
 * Explanation: 121 reads as 121 from left to right and from right to left.
 * 
 * Example 2:
 * 
 * Input: x = -121
 * Output: false
 * Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
 * 
 * Example 3:
 * 
 * Input: x = 10
 * Output: false
 * Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
 * 
 *  
 * Constraints:
 * 
 * 	-2^31 <= x <= 2^31 - 1
 * 
 *  
 * Follow up: Could you solve it without converting the integer to a string?
 */
pub struct Solution {}
// problem: https://leetcode.cn/problems/palindrome-number/
// discuss: https://leetcode.cn/problems/palindrome-number/discuss/?currentPage=1&orderBy=most_votes&query=
// submission codes start here
impl Solution {
    pub fn is_palindrome(x: i32) -> bool {
        if x == 0 {
            return true
        }
        if x < 0 || x % 10 == 0 {
            return false;
        }
        let mut reverse_half = x % 10;
        let mut x = x / 10;
        while x > reverse_half {
            reverse_half = reverse_half * 10 + x % 10;
            x = x / 10;
        }
        x == reverse_half || x == reverse_half / 10
    }
}
// submission codes end
#[cfg(test)]
mod tests {
    use super::*;
    #[test]
    fn test_9() {
        assert_eq!(true, Solution::is_palindrome(121));
        assert_eq!(false, Solution::is_palindrome(123));
        assert_eq!(false, Solution::is_palindrome(10));
        assert_eq!(true, Solution::is_palindrome(0));
    }
}