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@ -216,4 +216,5 @@ mod p3007_maximum_number_that_sum_of_the_prices_is_less_than_or_equal_to_k;
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mod p3133_minimum_array_end;
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mod p3145_find_products_of_elements_of_big_array;
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mod p3146_permutation_difference_between_two_strings;
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mod p698_partition_to_k_equal_sum_subsets;
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mod p698_partition_to_k_equal_sum_subsets;
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mod p3134_find_the_median_of_the_uniqueness_array;
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src/problem/p3134_find_the_median_of_the_uniqueness_array.rs
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src/problem/p3134_find_the_median_of_the_uniqueness_array.rs
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@ -0,0 +1,71 @@
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/**
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* [3134] Find the Median of the Uniqueness Array
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*/
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pub struct Solution {}
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// submission codes start here
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use std::collections::HashMap;
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impl Solution {
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pub fn median_of_uniqueness_array(nums: Vec<i32>) -> i32 {
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let n = nums.len() as i64;
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let median = (n * (n + 1) / 2 + 1) / 2;
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// 检查数组中不同元素数目小于等于t的连续子数组是否大于等于median
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let check = |t: i64| -> bool {
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let mut map = HashMap::new();
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let mut total = 0;
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let mut j = 0;
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for i in 0..n {
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let entry = map.entry(nums[i as usize]).or_insert(0);
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*entry += 1;
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while map.len() as i64 > t {
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let entry = map.get_mut(&nums[j]).unwrap();
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*entry -= 1;
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if *entry == 0 {
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map.remove(&nums[j]);
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}
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j += 1;
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}
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total += i - j as i64 + 1;
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}
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total >= median
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};
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let mut result = 0;
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let (mut left, mut right) = (1, n);
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while left <= right {
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let middle = (left + right) / 2;
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if check(middle) {
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result = middle;
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right = middle - 1;
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} else {
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left = middle + 1;
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}
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}
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result as i32
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}
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}
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// submission codes end
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#[cfg(test)]
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mod tests {
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use super::*;
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#[test]
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fn test_3134() {
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assert_eq!(1, Solution::median_of_uniqueness_array(vec![1, 2, 3]));
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assert_eq!(2, Solution::median_of_uniqueness_array(vec![3, 4, 3, 4, 5]));
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}
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}
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