修改SSTFGetQuery函数

This commit is contained in:
nvhaizi1 2022-06-02 09:02:04 +08:00
parent 8b64c30e5f
commit 2459ccb8f5

View File

@ -71,44 +71,45 @@ bus_query_t *FCFSQuery()
bus_query_t *SSTFGetQuery()
{
int a,b,length,min=10;//最多有10个站点
int a,b,length,min;
a = the_bus->rail_node_pos->id; //是当前公交车的位置,而不是站点位置
b=rails->last_node->id;//总的站点数
b = rails->last_node->id;//总的站点数
if (1 <= a <= b/2)
{
if(abs(a+b-queries->node->id) < abs(a-queries->node->id) )
if (abs(a+b-queries->node->id) < abs(a-queries->node->id) )
{
min=abs(a+b-queries->node->id);
min = abs(a+b-queries->node->id);
}
else
{
min=abs(a-queries->node->id);
min = abs(a-queries->node->id);
}
}
else if (b/2 < a <=b)
{
if (abs(queries->node->id+b-a)<abs(a-queries->node->id))
if (abs(queries->node->id+b-a) < abs(a-queries->node->id))
{
min=abs(queries->node->id+b-a);
min = abs(queries->node->id+b-a);
}
else
{
min=abs(a-queries->node->id);
min = abs(a-queries->node->id);
}
}
bus_query_t *p =queries->next_node;
bus_query_t *result=NULL;
while(queries->time != bus_time)
//通过上诉把第一个请求的距离置为最小值min
bus_query_t *p = queries->next_node;
bus_query_t *result = queries;//如果第一个请求即最近的那一个result=第一个请求
while (p->time <= bus_time)//在当前的时间找到所有请求中最近的一个
{
if (1 <= a <= b/2)
if (1 <= a <= b/2)//对当前站点所在的位置进行分类讨论
{
if(abs(a+b-p->node->id) <= abs(a-p->node->id) )
if (abs(a+b-p->node->id) <= abs(a-p->node->id) )
{
if(min >=abs(a+b-p->node->id))
if(min >= abs(a+b-p->node->id))
{
min=abs(a+b-p->node->id);
result=p;
p=p->next_node;
min = abs(a+b-p->node->id);
result = p;//把最小距离所对应的请求指针传给result
p = p->next_node;
}
}
}
@ -118,14 +119,14 @@ bus_query_t *SSTFGetQuery()
{
if (min >= abs(p->node->id+b-a))
{
min=abs(p->node->id+b-a);
result=p;
p=p->next_node;
min = abs(p->node->id+b-a);
result = p;
p = p->next_node;
}
}
}
}
return result;
return result;//需不需要返回空指针的情况呢?
}
int SSTFDirection(bus_query_t* query)